Optimal. Leaf size=181 \[ -\frac {b \tan (c+d x)}{d \left (a^2-b^2\right )}+\frac {\left (3 a^2-b^2\right ) \sec (c+d x)}{2 a d \left (a^2-b^2\right )}+\frac {b \cot (c+d x)}{a^2 d}-\frac {\left (3 a^2+2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{2 a^3 d}+\frac {2 b^5 \tan ^{-1}\left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{a^3 d \left (a^2-b^2\right )^{3/2}}-\frac {\csc ^2(c+d x) \sec (c+d x)}{2 a d} \]
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Rubi [A] time = 0.36, antiderivative size = 212, normalized size of antiderivative = 1.17, number of steps used = 17, number of rules used = 12, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.414, Rules used = {2898, 2622, 321, 207, 2620, 14, 288, 2696, 12, 2660, 618, 204} \[ \frac {2 b^5 \tan ^{-1}\left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{a^3 d \left (a^2-b^2\right )^{3/2}}+\frac {b^2 \sec (c+d x)}{a^3 d}-\frac {b^2 \tanh ^{-1}(\cos (c+d x))}{a^3 d}+\frac {b^3 \sec (c+d x) (b-a \sin (c+d x))}{a^3 d \left (a^2-b^2\right )}-\frac {b \tan (c+d x)}{a^2 d}+\frac {b \cot (c+d x)}{a^2 d}+\frac {3 \sec (c+d x)}{2 a d}-\frac {3 \tanh ^{-1}(\cos (c+d x))}{2 a d}-\frac {\csc ^2(c+d x) \sec (c+d x)}{2 a d} \]
Antiderivative was successfully verified.
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Rule 12
Rule 14
Rule 204
Rule 207
Rule 288
Rule 321
Rule 618
Rule 2620
Rule 2622
Rule 2660
Rule 2696
Rule 2898
Rubi steps
\begin {align*} \int \frac {\csc ^3(c+d x) \sec ^2(c+d x)}{a+b \sin (c+d x)} \, dx &=\int \left (\frac {b^2 \csc (c+d x) \sec ^2(c+d x)}{a^3}-\frac {b \csc ^2(c+d x) \sec ^2(c+d x)}{a^2}+\frac {\csc ^3(c+d x) \sec ^2(c+d x)}{a}-\frac {b^3 \sec ^2(c+d x)}{a^3 (a+b \sin (c+d x))}\right ) \, dx\\ &=\frac {\int \csc ^3(c+d x) \sec ^2(c+d x) \, dx}{a}-\frac {b \int \csc ^2(c+d x) \sec ^2(c+d x) \, dx}{a^2}+\frac {b^2 \int \csc (c+d x) \sec ^2(c+d x) \, dx}{a^3}-\frac {b^3 \int \frac {\sec ^2(c+d x)}{a+b \sin (c+d x)} \, dx}{a^3}\\ &=\frac {b^3 \sec (c+d x) (b-a \sin (c+d x))}{a^3 \left (a^2-b^2\right ) d}+\frac {b^3 \int \frac {b^2}{a+b \sin (c+d x)} \, dx}{a^3 \left (a^2-b^2\right )}+\frac {\operatorname {Subst}\left (\int \frac {x^4}{\left (-1+x^2\right )^2} \, dx,x,\sec (c+d x)\right )}{a d}-\frac {b \operatorname {Subst}\left (\int \frac {1+x^2}{x^2} \, dx,x,\tan (c+d x)\right )}{a^2 d}+\frac {b^2 \operatorname {Subst}\left (\int \frac {x^2}{-1+x^2} \, dx,x,\sec (c+d x)\right )}{a^3 d}\\ &=\frac {b^2 \sec (c+d x)}{a^3 d}-\frac {\csc ^2(c+d x) \sec (c+d x)}{2 a d}+\frac {b^3 \sec (c+d x) (b-a \sin (c+d x))}{a^3 \left (a^2-b^2\right ) d}+\frac {b^5 \int \frac {1}{a+b \sin (c+d x)} \, dx}{a^3 \left (a^2-b^2\right )}+\frac {3 \operatorname {Subst}\left (\int \frac {x^2}{-1+x^2} \, dx,x,\sec (c+d x)\right )}{2 a d}-\frac {b \operatorname {Subst}\left (\int \left (1+\frac {1}{x^2}\right ) \, dx,x,\tan (c+d x)\right )}{a^2 d}+\frac {b^2 \operatorname {Subst}\left (\int \frac {1}{-1+x^2} \, dx,x,\sec (c+d x)\right )}{a^3 d}\\ &=-\frac {b^2 \tanh ^{-1}(\cos (c+d x))}{a^3 d}+\frac {b \cot (c+d x)}{a^2 d}+\frac {3 \sec (c+d x)}{2 a d}+\frac {b^2 \sec (c+d x)}{a^3 d}-\frac {\csc ^2(c+d x) \sec (c+d x)}{2 a d}+\frac {b^3 \sec (c+d x) (b-a \sin (c+d x))}{a^3 \left (a^2-b^2\right ) d}-\frac {b \tan (c+d x)}{a^2 d}+\frac {3 \operatorname {Subst}\left (\int \frac {1}{-1+x^2} \, dx,x,\sec (c+d x)\right )}{2 a d}+\frac {\left (2 b^5\right ) \operatorname {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{a^3 \left (a^2-b^2\right ) d}\\ &=-\frac {3 \tanh ^{-1}(\cos (c+d x))}{2 a d}-\frac {b^2 \tanh ^{-1}(\cos (c+d x))}{a^3 d}+\frac {b \cot (c+d x)}{a^2 d}+\frac {3 \sec (c+d x)}{2 a d}+\frac {b^2 \sec (c+d x)}{a^3 d}-\frac {\csc ^2(c+d x) \sec (c+d x)}{2 a d}+\frac {b^3 \sec (c+d x) (b-a \sin (c+d x))}{a^3 \left (a^2-b^2\right ) d}-\frac {b \tan (c+d x)}{a^2 d}-\frac {\left (4 b^5\right ) \operatorname {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{a^3 \left (a^2-b^2\right ) d}\\ &=\frac {2 b^5 \tan ^{-1}\left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 \left (a^2-b^2\right )^{3/2} d}-\frac {3 \tanh ^{-1}(\cos (c+d x))}{2 a d}-\frac {b^2 \tanh ^{-1}(\cos (c+d x))}{a^3 d}+\frac {b \cot (c+d x)}{a^2 d}+\frac {3 \sec (c+d x)}{2 a d}+\frac {b^2 \sec (c+d x)}{a^3 d}-\frac {\csc ^2(c+d x) \sec (c+d x)}{2 a d}+\frac {b^3 \sec (c+d x) (b-a \sin (c+d x))}{a^3 \left (a^2-b^2\right ) d}-\frac {b \tan (c+d x)}{a^2 d}\\ \end {align*}
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Mathematica [A] time = 3.10, size = 261, normalized size = 1.44 \[ \frac {-\frac {4 b \tan \left (\frac {1}{2} (c+d x)\right )}{a^2}+\frac {4 b \cot \left (\frac {1}{2} (c+d x)\right )}{a^2}+\frac {4 \left (3 a^2+2 b^2\right ) \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )}{a^3}-\frac {4 \left (3 a^2+2 b^2\right ) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )}{a^3}+\frac {16 b^5 \tan ^{-1}\left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{a^3 \left (a^2-b^2\right )^{3/2}}+\frac {8 \sin \left (\frac {1}{2} (c+d x)\right )}{(a+b) \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )}-\frac {8 \sin \left (\frac {1}{2} (c+d x)\right )}{(a-b) \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )}-\frac {\csc ^2\left (\frac {1}{2} (c+d x)\right )}{a}+\frac {\sec ^2\left (\frac {1}{2} (c+d x)\right )}{a}}{8 d} \]
Antiderivative was successfully verified.
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fricas [B] time = 1.91, size = 878, normalized size = 4.85 \[ \left [-\frac {4 \, a^{6} - 4 \, a^{4} b^{2} - 2 \, {\left (3 \, a^{6} - 4 \, a^{4} b^{2} + a^{2} b^{4}\right )} \cos \left (d x + c\right )^{2} - 2 \, {\left (b^{5} \cos \left (d x + c\right )^{3} - b^{5} \cos \left (d x + c\right )\right )} \sqrt {-a^{2} + b^{2}} \log \left (-\frac {{\left (2 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2} - 2 \, {\left (a \cos \left (d x + c\right ) \sin \left (d x + c\right ) + b \cos \left (d x + c\right )\right )} \sqrt {-a^{2} + b^{2}}}{b^{2} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2}}\right ) + {\left ({\left (3 \, a^{6} - 4 \, a^{4} b^{2} - a^{2} b^{4} + 2 \, b^{6}\right )} \cos \left (d x + c\right )^{3} - {\left (3 \, a^{6} - 4 \, a^{4} b^{2} - a^{2} b^{4} + 2 \, b^{6}\right )} \cos \left (d x + c\right )\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) - {\left ({\left (3 \, a^{6} - 4 \, a^{4} b^{2} - a^{2} b^{4} + 2 \, b^{6}\right )} \cos \left (d x + c\right )^{3} - {\left (3 \, a^{6} - 4 \, a^{4} b^{2} - a^{2} b^{4} + 2 \, b^{6}\right )} \cos \left (d x + c\right )\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) - 4 \, {\left (a^{5} b - a^{3} b^{3} - {\left (2 \, a^{5} b - 3 \, a^{3} b^{3} + a b^{5}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{4 \, {\left ({\left (a^{7} - 2 \, a^{5} b^{2} + a^{3} b^{4}\right )} d \cos \left (d x + c\right )^{3} - {\left (a^{7} - 2 \, a^{5} b^{2} + a^{3} b^{4}\right )} d \cos \left (d x + c\right )\right )}}, -\frac {4 \, a^{6} - 4 \, a^{4} b^{2} - 2 \, {\left (3 \, a^{6} - 4 \, a^{4} b^{2} + a^{2} b^{4}\right )} \cos \left (d x + c\right )^{2} + 4 \, {\left (b^{5} \cos \left (d x + c\right )^{3} - b^{5} \cos \left (d x + c\right )\right )} \sqrt {a^{2} - b^{2}} \arctan \left (-\frac {a \sin \left (d x + c\right ) + b}{\sqrt {a^{2} - b^{2}} \cos \left (d x + c\right )}\right ) + {\left ({\left (3 \, a^{6} - 4 \, a^{4} b^{2} - a^{2} b^{4} + 2 \, b^{6}\right )} \cos \left (d x + c\right )^{3} - {\left (3 \, a^{6} - 4 \, a^{4} b^{2} - a^{2} b^{4} + 2 \, b^{6}\right )} \cos \left (d x + c\right )\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) - {\left ({\left (3 \, a^{6} - 4 \, a^{4} b^{2} - a^{2} b^{4} + 2 \, b^{6}\right )} \cos \left (d x + c\right )^{3} - {\left (3 \, a^{6} - 4 \, a^{4} b^{2} - a^{2} b^{4} + 2 \, b^{6}\right )} \cos \left (d x + c\right )\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) - 4 \, {\left (a^{5} b - a^{3} b^{3} - {\left (2 \, a^{5} b - 3 \, a^{3} b^{3} + a b^{5}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{4 \, {\left ({\left (a^{7} - 2 \, a^{5} b^{2} + a^{3} b^{4}\right )} d \cos \left (d x + c\right )^{3} - {\left (a^{7} - 2 \, a^{5} b^{2} + a^{3} b^{4}\right )} d \cos \left (d x + c\right )\right )}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.24, size = 245, normalized size = 1.35 \[ \frac {\frac {16 \, {\left (\pi \left \lfloor \frac {d x + c}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\relax (a) + \arctan \left (\frac {a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + b}{\sqrt {a^{2} - b^{2}}}\right )\right )} b^{5}}{{\left (a^{5} - a^{3} b^{2}\right )} \sqrt {a^{2} - b^{2}}} + \frac {16 \, {\left (b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - a\right )}}{{\left (a^{2} - b^{2}\right )} {\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}} + \frac {a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 4 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{a^{2}} + \frac {4 \, {\left (3 \, a^{2} + 2 \, b^{2}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right )}{a^{3}} - \frac {18 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 12 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 4 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + a^{2}}{a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2}}}{8 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.50, size = 227, normalized size = 1.25 \[ -\frac {1}{d \left (a +b \right ) \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}+\frac {\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )}{8 a d}-\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) b}{2 d \,a^{2}}-\frac {1}{8 a d \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}+\frac {3 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 a d}+\frac {\ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}}{d \,a^{3}}+\frac {b}{2 d \,a^{2} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}+\frac {1}{d \left (a -b \right ) \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}+\frac {2 b^{5} \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{d \,a^{3} \left (a -b \right ) \left (a +b \right ) \sqrt {a^{2}-b^{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 15.35, size = 1570, normalized size = 8.67 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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